Duration: 40 minutes
By the end of this lesson, you should be able to:
Solving a triangle = Find ALL missing sides and angles
Use:
(Plus we always have the 90 degrees angle!)
Given: angle A = 35 degrees, hypotenuse = 20 cm
Find: all other parts
Angle B: 180 - 90 - 35 = 55 degrees
Opposite: sin 35 degrees = opp/20 opp = 20 × 0.574 = 11.47 cm
Adjacent: cos 35 degrees = adj/20 adj = 20 × 0.819 = 16.38 cm
Check: 11.47² + 16.38² ≈ 20² ✓
Given: angle theta = 40 degrees, opposite = 12 cm
Angle: 180 - 90 - 40 = 50 degrees
Hypotenuse: sin 40 degrees = 12/hyp hyp = 12/0.643 ≈ 18.67 cm
Adjacent: tan 40 degrees = 12/adj adj = 12/0.839 ≈ 14.30 cm
Given: angle = 55 degrees, adjacent = 10 cm
Given: hypotenuse = 25 cm, opposite = 15 cm
Adjacent: √(25² - 15²) = √400 = 20 cm
Angle A: sin A = 15/25 = 0.6 A = sin⁻¹(0.6) ≈ 36.9 degrees
Angle B: 180 - 90 - 36.9 = 53.1 degrees
Given angle + side:
Given two sides:
Given: angle = 28 degrees, hypotenuse = 30 cm
Find: all parts
Given: adjacent = 9 cm, hypotenuse = 15 cm
Problem: A ladder 5 m long leans against a wall. The base is 2 m from the wall.
Height: √(5² - 2²) = √21 ≈ 4.58 m
Angle: cos theta = 2/5 theta = cos⁻¹(0.4) ≈ 66.4 degrees
Three ways to verify:
Always check!
Given: angle A = 32 degrees, opposite = 8 cm
Find: all other sides and angles
Check: 8² + 12.80² ≈ 15.09² ✓
Solve completely (find all missing parts):
Lesson 7: Angles of Elevation and Depression
You now have ALL the tools to solve any right triangle!
Practice makes perfect!
Created: December 2025 Based on: NCDC Lower Secondary Mathematics Syllabus (2019)
Source: National Curriculum Development Centre (NCDC), Uganda