Duration: 40 minutes
By the end of this lesson, you should be able to:
From Lesson 3:
Make x the subject of y = 3x
Answer: x = y/3 (divide both sides by 3)
What if there are two operations to undo?
Formula: y = 2x + 5
What operations are done to x?
To undo, we work backwards!
Make x the subject
Step 1: Undo "add 5" - subtract 5 from both sides y - 5 = 2x + 5 - 5 y - 5 = 2x
Step 2: Undo "multiply by 2" - divide both sides by 2 (y - 5)/2 = x
x = (y - 5)/2
Make a the subject
Operations on a: multiply by t, then add u
Step 1: Subtract u from both sides v - u = at
Step 2: Divide both sides by t (v - u)/t = a
a = (v - u)/t
Make l the subject
Operations on l: multiply by 2, then add 2w
Step 1: Subtract 2w P - 2w = 2l
Step 2: Divide by 2 (P - 2w)/2 = l
l = (P - 2w)/2
Make the indicated variable the subject:
a = 3b - 7
y = (x + 4)/2
Formula: s = d/t
Make t the subject
t is in the denominator, so first multiply both sides by t
st = d
Then divide by s: t = d/s
Formula: A = pi r squared
Make r the subject
Operations on r: square, then multiply by pi
Step 1: Divide by pi A/pi = r squared
Step 2: Take the square root sqrt(A/pi) = r
r = sqrt(A/pi)
Remember: Square root undoes squaring!
Make v the subject
Step 1: Multiply by 2 2E = mv squared
Step 2: Divide by m 2E/m = v squared
Step 3: Take the square root v = sqrt(2E/m)
C = 2 pi r r = C/(2 pi)
V = pi r squared h h = V/(pi r squared)
v squared = u squared + 2as
Multi-step rearrangement process:
y = 4x - 3 x = (y + 3)/4
A = pi r squared r = sqrt(A/pi)
s = ut + (1/2)at squared
Lesson 5: Solving Linear Equations Review
We will apply our skills to:
Created: December 2025 Based on: NCDC Lower Secondary Mathematics Syllabus (2019)
Source: National Curriculum Development Centre (NCDC), Uganda