Back to Exercise: Understand independence via the product rule

Exercises: Understand Independence Through the Product Rule

Work through each section in order. For independence tests, compute P(A)P(A), P(B)P(B), and P(A and B)P(A \text{ and } B), then compare P(A and B)P(A \text{ and } B) to the product P(A)⋅P(B)P(A) \cdot P(B). For explanation problems, write in complete sentences.

Grade 10·21 problems·~35 min·Common Core Math - HS Statistics and Probability·group·hss-cp-a-2
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A

Warm-Up: Probability Foundations

These problems review skills you already know.

1

A fair coin is flipped twice. Listing the sample space {HH,HT,TH,TT}\{HH, HT, TH, TT\}, what is P(both heads)P(\text{both heads})? Express your answer as a fraction.

2

Which statement about the word "independent" in probability is correct?

A.

Independence is a relationship between two events: AA is independent of BB.

B.

Independence is a property a single event has on its own.

C.

An event is independent whenever its probability is greater than 0.50.5.

D.

Independence only describes events from two separate experiments.

3

Two events AA and BB are mutually exclusive when they cannot both occur. What is P(A and B)P(A \text{ and } B) for mutually exclusive events?

A.

P(A and B)=0P(A \text{ and } B) = 0

B.

P(A and B)=P(A)⋅P(B)P(A \text{ and } B) = P(A) \cdot P(B)

C.

P(A and B)=P(A)+P(B)P(A \text{ and } B) = P(A) + P(B)

D.

P(A and B)=1P(A \text{ and } B) = 1

B

Fluency Practice

Test each pair of events using the product rule.

1

Two fair coins are flipped. Let $A = $ "first coin is heads" and $B = $ "second coin is heads." Compute P(A)⋅P(B)P(A) \cdot P(B). Express your answer as a fraction.

2

A fair die is rolled once. Let $A = $ "even" ={2,4,6}= \{2, 4, 6\} and $B = $ "greater than 2" ={3,4,5,6}= \{3, 4, 5, 6\}. Compute P(A and B)P(A \text{ and } B) directly by counting the outcomes in both events. Express your answer as a fraction.

3

Using the same die events, $A = $ "even" and $B = $ "greater than 2," we have P(A)=12P(A) = \frac{1}{2}, P(B)=23P(B) = \frac{2}{3}, and P(A and B)=13P(A \text{ and } B) = \frac{1}{3}. Are AA and BB independent?

A.

Yes — P(A)⋅P(B)=12⋅23=13=P(A and B)P(A) \cdot P(B) = \frac{1}{2} \cdot \frac{2}{3} = \frac{1}{3} = P(A \text{ and } B), so the product rule holds.

B.

No — the two events come from the same die, so they cannot be independent.

C.

No — P(A)⋅P(B)=12⋅23=23≠13P(A) \cdot P(B) = \frac{1}{2} \cdot \frac{2}{3} = \frac{2}{3} \neq \frac{1}{3}.

D.

Cannot tell without listing the full sample space again.

4

A spinner lands on red with probability 0.40.4. It is spun twice, and the two spins are independent. What is the probability it lands on red both times? Give a decimal.

5

You are told P(A)=0.5P(A) = 0.5, P(B)=0.4P(B) = 0.4, and P(A and B)=0.25P(A \text{ and } B) = 0.25. Are AA and BB independent?

A.

No — P(A)⋅P(B)=0.20≠0.25P(A) \cdot P(B) = 0.20 \neq 0.25, so the product rule fails and the events are dependent.

B.

Yes — both probabilities are positive, so the events must be independent.

C.

Yes — 0.250.25 is close enough to 0.200.20 that we call them independent.

D.

Cannot decide without knowing the experiment.

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