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Central and Inscribed Angles | Lesson 3 of 5

Central and Inscribed Angles

SAT Math — Geometry & Trigonometry

In this lesson:

  • An arc's measure is its central angle — not its length
  • Inscribed angles equal half the intercepted arc
  • Inscribed angles on the same arc are congruent
  • An inscribed angle on a diameter is always 90°
Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

What You Will Learn Today

  1. Find angles, arc measures, and lengths; use isosceles and right triangles
  2. State an arc's measure from its central angle, not its length
  3. Inscribed angle = ½ × intercepted arc
  4. Inscribed angles on the same arc are congruent
  5. Inscribed angle in a semicircle = 90°
Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Connecting to What You Know Already

Ten-second check: a central angle cuts off what fraction of the circle? A quarter.

You also know:

  • A chord connects two points on a circle

New today: an arc's measure is its central angle in degrees — not its length.

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Arc Measure Is Not Arc Length

Two circles, radius 2 and radius 4, each with a 90 degree central angle: both arcs measure 90 degrees, lengths π and 2π

Lengths: and

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Central Angles: Vertex at the Center

A central angle has its vertex at the center. Its sides are radii.

Rule: Central angle = intercepted arc (same measure)

Example:

  • Minor arc
  • Major arc
Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Inscribed Angle Is Half the Central Angle

Side-by-side diagram of central angle AOB = 120° and inscribed angle ACB = 60° intercepting the same arc AB

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

The Inscribed Angle Theorem Explained

An inscribed angle has its vertex on the circle and its sides are chords.

Theorem: Inscribed angle = ½ × intercepted arc

Vertex location rule:

  • Vertex at center → angle equals arc
  • Vertex on circle → angle = half the arc
Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Three Examples: Find the Angle or Arc

Arc : inscribed angle

Inscribed angle : arc

Central angle , same arc: inscribed angle

Identify the intercepted arc first, then apply the theorem.

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Inscribed Angles Sharing the Same Arc

Corollary: Inscribed angles intercepting the same arc are congruent.

Two inscribed angles ACB and ADB at different points C and D on the major arc, both intercepting arc AB, each labeled 50°

If , then .

Different arcs: gives , gives .

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

The Semicircle Theorem: Diameter Makes 90°

An inscribed angle subtending a diameter is always 90°.

Why: a diameter cuts off a arc, so the angle is

Converse: A 90° inscribed angle means the chord is a diameter.

Scan every circle diagram for a diameter. Mark that angle 90°.

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Inscribed Right Triangle: Find the Diameter

Right triangle ABC inscribed in a circle with AB as horizontal diameter labeled 10, right angle square in red at C labeled 90°, legs AC = 6 and BC = 8

→ is a diameter: , radius .

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Quick Check: What Does 90° Tell You?

In a circle, inscribed angle .

What can you conclude about chord ?

Think before advancing...

Answer: A 90° inscribed angle means the subtended chord is a diameter. Chord is a diameter of the circle.

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

SAT Problem 1: One Arc, Two Vertices

Circle with center O, central angle AOB = 100°, point C on the major arc with angle ACB = 50°, point D on the minor arc with angle ADB = 130°

Steps: (1) identify arcs; (2) central angle gives arc measure; (3) inscribed angle theorem.

. Arc , so . is on the minor arc, so it intercepts the major arc: , .

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

SAT Problem 2: Radii Make an Isosceles Triangle

Same circle: OA and OB are radii, so triangle OAB is isosceles with apex angle 100°

In the same figure, (radii), so is isosceles.

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

SAT Problem 3: Semicircle and Pythagorean Theorem

Diameter , . Find .

Step 1: on circle + is diameter →

Step 2:

5-12-13 Pythagorean triple

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Summary: The Five Key Rules

✓ Arc measure = central angle, in degrees (not length)
✓ Inscribed angle = ½ × intercepted arc (vertex on circle)
✓ Same-arc corollary: same arc, congruent angles
✓ Semicircle theorem: angle on a diameter = 90°; converse holds
✓ Two radii make an isosceles triangle

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Watch Out: Five Common Mistakes

⚠️ Inscribed angle ≠ arc — it equals half the arc
⚠️ Intercepted arc is opposite the vertex
⚠️ Vertex inside the circle? Not inscribed
⚠️ Corollary: only angles on the same arc
⚠️ Diameter in a diagram → mark the inscribed angle 90°

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles
Central and Inscribed Angles | Lesson 3 of 5

Coming Up: Tangent Lines and Chord Properties

Next lesson covers:

  • Tangent-radius perpendicularity
  • Tangent segments from an external point
  • Chord intersection and segment relationships

Like today's semicircle problems, many of these come down to finding a right triangle.

Grade 10 Geometry | SAT Math — Geometry & Trigonometry: Circles